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4n^2-17n+7=0
a = 4; b = -17; c = +7;
Δ = b2-4ac
Δ = -172-4·4·7
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{177}}{2*4}=\frac{17-\sqrt{177}}{8} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{177}}{2*4}=\frac{17+\sqrt{177}}{8} $
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